b^2+10b+42=

Solution for b^2+10b+42= equation:

Simplifying
b2 + 10b + 42 = 0

Reorder the terms:
42 + 10b + b2 = 0

Solving
42 + 10b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-42' to each side of the equation.
42 + 10b + -42 + b2 = 0 + -42

Reorder the terms:
42 + -42 + 10b + b2 = 0 + -42

Combine like terms: 42 + -42 = 0
0 + 10b + b2 = 0 + -42
10b + b2 = 0 + -42

Combine like terms: 0 + -42 = -42
10b + b2 = -42

The b term is 10b.  Take half its coefficient (5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
10b + 25 + b2 = -42 + 25

Reorder the terms:
25 + 10b + b2 = -42 + 25

Combine like terms: -42 + 25 = -17
25 + 10b + b2 = -17

Factor a perfect square on the left side:
(b + 5)(b + 5) = -17

Can't calculate square root of the right side.

The solution to this equation could not be determined.